1) distance parcourue :
d = (9,81 x t^2) / 2
t = 1s
d = (9,81 x 1^2) / 2
d = 9,81 / 2
d = 4,905 m
t = 2s
d = (9,81 x 2^2) / 2
d = (9,81 x 4) / 2
d = 19,62 m
t = 5s
d = (9,81 x 5^2) / 2
d = (9,81 x 25) / 2
d = 122,625 m
t = 10s
d = (9,81 x 10^2) / 2
d = (9,81 x 100) / 2
d = 490,5 m
t (s) ..... 1 ................. 2 ............. 5 ...........10 ........
d(m).... 4,905......19,62........122,625....490,5...
Oui c'est proportionnel car :
d = (9,81 x t^2) / 2
d = 9,81 / 2 x t^2
d = 4,905 t^2
d = 2000 m
t^2 = d / 4,905
t^2 = 2000 / 4,905
t = V(2000 / 4,905). (Avec V = racine)
t = 20,19 s
