Salut;
A=[tex] \frac{11}{3} - \frac{8}{3} x \frac{5}{(-16)} = \frac{11}{3}- \frac{4x2}{3}x \frac{5}{(-4)x4} = \frac{11}{3} + \frac{2}{3} x \frac{5}{4} = \frac{44}{12} + \frac{10}{12}= \frac{54/6}{12/6} = \frac{9}{2} [/tex]
B=[tex] \frac{1- \frac{3}{2}+ \frac{9}{7} }{ \frac{5}{4}+ \frac{1}{3} } = \frac{ \frac{-1}{2} + \frac{9}{7} }{ \frac{11}{12} } = \frac{ \frac{11}{14} }{ \frac{11}{12} } = \frac{11}{14} x \frac{12}{11} = \frac{6}{7} [/tex]
C=[tex] \frac{2x10^3x5x(10^{-5})^2 }{20} = \frac{2x5}{20} x10^3x(10^{-5})^{2} = \frac{10}{20}x10 x^{-7} = \frac{1}{2} x10^{-7} [/tex]
vérifie bien
