(1-2x)(3x-6) \ (x+1) <0
(1-2x)(x-2) \ (x+1) <0
tab signes :
x -inf -1 0,5 2 +inf
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1-2x + + 0 - -
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x-2 - - - 0 +
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x+1 - 0 + + +
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f(x) + || - 0 + 0 -
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donc S=]-1;0,5[ U ]2;+∞[