Bonsoir Kobe107
PPCM(4,5,6)=60
On réduit toutes les fractions avec 60 au dénominateur.
[tex]\dfrac{3}{4}=\dfrac{3\times15}{4\times15}=\dfrac{45}{60}\\\\\dfrac{5}{5}=1=\dfrac{60}{60}\\\\\dfrac{5}{6}=\dfrac{5\times10}{6\times10}=\dfrac{50}{60}\\\\\dfrac{4}{3}=\dfrac{4\times20}{3\times20}=\dfrac{80}{60}\\\\\dfrac{5}{4}=\dfrac{5\times15}{4\times15}=\dfrac{75}{60}\\\\\dfrac{6}{5}=\dfrac{6\times12}{5\times12}=\dfrac{72}{60}[/tex]
[tex]\dfrac{45}{60}\ \textless \ \dfrac{50}{60}\ \textless \ \dfrac{60}{60}\ \textless \ \dfrac{72}{60}\ \textless \ \dfrac{75}{60}\ \textless \ \dfrac{80}{60}[/tex]
Donc,
[tex]\boxed{\dfrac{3}{4}\ \textless \ \dfrac{5}{6}\ \textless \ \dfrac{5}{5}\ \textless \ \dfrac{6}{5}\ \textless \ \dfrac{5}{4}\ \textless \ \dfrac{4}{3}}[/tex]
